题目链接:力扣
用列表生成式检查前缀,如果包含指定前缀,就生成个1,最后用sum求和,一行搞定!
class Solution:
def prefixCount(self, words: List[str], pref: str) -> int:
return sum([1 for i in words if i.startswith(pref) ])
页面更新:2024-04-05
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